I've written spark job:
object SimpleApp {
def main(args: Array[String]) {
val conf = new SparkConf().setAppName("Simple Application").setMaster("local")
val sc = new SparkContext(conf)
val ctx = new org.apache.spark.sql.SQLContext(sc)
import ctx.implicits._
case class Person(age: Long, city: String, id: String, lname: String, name: String, sex: String)
case class Person2(name: String, age: Long, city: String)
val persons = ctx.read.json("/tmp/persons.json").as[Person]
persons.printSchema()
}
}
In IDE when I run the main function, 2 error occurs:
Error:(15, 67) Unable to find encoder for type stored in a Dataset. Primitive types (Int, String, etc) and Product types (case classes) are supported by importing sqlContext.implicits._ Support for serializing other types will be added in future releases.
val persons = ctx.read.json("/tmp/persons.json").as[Person]
^
Error:(15, 67) not enough arguments for method as: (implicit evidence$1: org.apache.spark.sql.Encoder[Person])org.apache.spark.sql.Dataset[Person].
Unspecified value parameter evidence$1.
val persons = ctx.read.json("/tmp/persons.json").as[Person]
^
but in Spark Shell I can run this job without any error. what is the problem?
The error message says that the Encoder
is not able to take the Person
case class.
Error:(15, 67) Unable to find encoder for type stored in a Dataset. Primitive types (Int, String, etc) and Product types (case classes) are supported by importing sqlContext.implicits._ Support for serializing other types will be added in future releases.
Move the declaration of the case class outside the scope of SimpleApp
.