Spark 2.0 (final) with Scala 2.11.8. The following super simple code yields the compilation error Error:(17, 45) Unable to find encoder for type stored in a Dataset. Primitive types (Int, String, etc) and Product types (case classes) are supported by importing spark.implicits._ Support for serializing other types will be added in future releases.
import org.apache.spark.sql.SparkSession
case class SimpleTuple(id: Int, desc: String)
object DatasetTest {
val dataList = List(
SimpleTuple(5, "abc"),
SimpleTuple(6, "bcd")
)
def main(args: Array[String]): Unit = {
val sparkSession = SparkSession.builder.
master("local")
.appName("example")
.getOrCreate()
val dataset = sparkSession.createDataset(dataList)
}
}
Spark Datasets
require Encoders
for data type which is about to be stored. For common types (atomics, product types) there is a number of predefined encoders available but you have to import these first from SparkSession.implicits
to make it work:
val sparkSession: SparkSession = ???
import sparkSession.implicits._
val dataset = sparkSession.createDataset(dataList)
Alternatively you can provide directly an explicit
import org.apache.spark.sql.{Encoder, Encoders}
val dataset = sparkSession.createDataset(dataList)(Encoders.product[SimpleTuple])
or implicit
implicit val enc: Encoder[SimpleTuple] = Encoders.product[SimpleTuple]
val dataset = sparkSession.createDataset(dataList)
Encoder
for the stored type.
Note that Encoders
also provide a number of predefined Encoders
for atomic types, and Encoders
for complex ones, can derived with ExpressionEncoder
.
Further reading:
Row
objects you have to provide Encoder
explicitly as shown in Encoder error while trying to map dataframe row to updated row