I'm unable to find a way of performing cross validation on a regression random forest model that I'm trying to produce.
So I have a dataset containing 1664 explanatory variables (different chemical properties), with one response variable (retention time). I'm trying to produce a regression random forest model in order to be able to predict the chemical properties of something given its retention time.
ID RT (seconds) 1_MW 2_AMW 3_Sv 4_Se
4281 38 145.29 5.01 14.76 28.37
4952 40 132.19 6.29 11 21.28
4823 41 176.21 7.34 12.9 24.92
3840 41 174.24 6.7 13.99 26.48
3665 42 240.34 9.24 15.2 27.08
3591 42 161.23 6.2 13.71 26.27
3659 42 146.22 6.09 12.6 24.16
This is an example of the table that I have. I want to basically plot RT against 1_MW, etc (up to 1664 variables), so I can find which of these variables are of importance and which aren't.
I do:-
r = randomForest(RT..seconds.~., data = cadets, importance =TRUE, do.trace = 100)
varImpPlot(r)
which tells me which variables are of importance and what not, which is great. However, I want to be able to partition my dataset so that I can perform cross validation on it. I found an online tutorial that explained how to do it, but for a classification model rather than regression.
I understand you do:-
k = 10
n = floor(nrow(cadets)/k)
i = 1
s1 = ((i-1) * n+1)
s2 = (i * n)
subset = s1:s2
to define how many cross folds you want to do, and the size of each fold, and to set the starting and end value of the subset. However, I don't know what to do here on after. I was told to loop through but I honestly have no idea how to do this. Nor do I know how to then plot the validation set and the test set onto the same graph to depict the level of accuracy/error.
If you could please help me with this I'd be ever so grateful, thanks!
From the source:
The out-of-bag (oob) error estimate
In random forests, there is no need for cross-validation or a separate test set to get an unbiased estimate of the test set error. It is estimated internally , during the run...
In particular, predict.randomForest
returns the out-of-bag prediction if newdata
is not given.