EDIT: this question arose back with pandas ~0.13 and was obsoleted by direct support somewhere between version 0.15-0.18 (as per @Cireo's late answer)
I can get a boxplot
of a salary column in a pandas DataFrame...
train.boxplot(column='Salary', by='Category', sym='')
...however I can't figure out how to define the index-order used on column 'Category' - I want to supply my own custom order, according to another criterion:
category_order_by_mean_salary = train.groupby('Category')['Salary'].mean().order().keys()
How can I apply my custom column order to the boxplot columns? (other than ugly kludging the column names with a prefix to force ordering)
'Category' is a string (really, should be a categorical, but this was back in 0.13, where categorical was a third-class citizen) column taking 27 distinct values: ['Accounting & Finance Jobs','Admin Jobs',...,'Travel Jobs']
. So it can be easily factorized with pd.Categorical.from_array()
On inspection, the limitation is inside pandas.tools.plotting.py:boxplot()
, which converts the column object without allowing ordering:
I suppose I could either hack up a custom version of pandas boxplot(), or reach into the internals of the object. And also file an enhance request.
Hard to say how to do this without a working example. My first guess would be to just add an integer column with the orders that you want.
A simple, brute-force way would be to add each boxplot one at a time.
import numpy as np
import pandas as pd
import matplotlib.pyplot as plt
df = pd.DataFrame(np.random.rand(37,4), columns=list('ABCD'))
columns_my_order = ['C', 'A', 'D', 'B']
fig, ax = plt.subplots()
for position, column in enumerate(columns_my_order):
ax.boxplot(df[column], positions=[position])
ax.set_xticks(range(position+1))
ax.set_xticklabels(columns_my_order)
ax.set_xlim(xmin=-0.5)
plt.show()