How to create a class literal of a known type: Class<List<String>>

skaffman picture skaffman · Jan 6, 2010 · Viewed 79.6k times · Source

Take the following:

public Class<List<String>> getObjectType() {
    // what can I return here?
}

What class literal expression can I return from this method which will satisfy the generics and compile? List.class won't compile, and neither will List.<String>class.

If you're wondering "why", I'm writing an implementation of Spring's FactoryBean<List<String>>, which requires me to implement Class<List<String>> getObjectType(). However, this is not a Spring question.

edit: My plaintive cries have been heard by the powers that be at SpringSource, and so Spring 3.0.1 will have the return type of getObjectType() changed to Class<?>, which neatly avoids the problem.

Answer

Bozho picture Bozho · Jan 6, 2010

You can always cast to what you need, like this

return (Class<List<String>>) new ArrayList<String>().getClass();

or

return (Class<List<String>>) Collections.<String>emptyList().getClass();

But I assume that's not what you are after. Well it works, with a warning, but it isn't exactly "beautiful".

I just found this

Why is there no class literal for wildcard parameterized types?

Because a wildcard parameterized type has no exact runtime type representation.

So casting might be the only way to go.