I have a generics class, Foo<T>
. In a method of Foo
, I want to get the class instance of type T
, but I just can't call T.class
.
What is the preferred way to get around it using T.class
?
The short answer is, that there is no way to find out the runtime type of generic type parameters in Java. I suggest reading the chapter about type erasure in the Java Tutorial for more details.
A popular solution to this is to pass the Class
of the type parameter into the constructor of the generic type, e.g.
class Foo<T> {
final Class<T> typeParameterClass;
public Foo(Class<T> typeParameterClass) {
this.typeParameterClass = typeParameterClass;
}
public void bar() {
// you can access the typeParameterClass here and do whatever you like
}
}