Applying one function to the result of another is known as function composition: `(f.g)(x) = f(g(x))`
What is the difference between the dot (.) and the dollar sign ($)? As I understand it, they are both syntactic sugar …
haskell syntax function-compositionI'm trying to understand what the dot operator is doing in this Haskell code: sumEuler = sum . (map euler) . mkList The …
haskell syntax function-compositionI have an array of functions and I'm trying to produce one function which consists of the composition of the …
python functional-programming composition function-compositionI have been reading Real World Haskell, and I am nearing the end, but a matter of style has been …
haskell coding-style function-compositionOkay, so I am not a Haskell programmer, but I am absolutely intrigued by a lot of the ideas behind …
haskell monads composition currying function-compositionI encountered andThen, but did not properly understand it. To look at it further, I read the Function1.andThen docs …
scala function-compositionI am currently coding some cryptographic algorithms in C++11 that require a lot of function compositions. There are 2 types of …
c++ c++11 function-compositionI really wish that Google was better at searching for syntax: decades :: (RealFrac a) => a -> a -&…
haskell syntax operators function-compositionOrdinary function composition is of the type (.) :: (b -> c) -> (a -> b) -> a …
haskell function-composition pointfreeMathematically the function composition operation is associative. Hence: f . (g . h) = (f . g) . h Thus the function composition operation may …
haskell function-composition associativity