The Java class DecimalFormat is a concrete subclass of NumberFormat that is used to format decimal numbers.
public static String formatAmountUpToTwoDecimalNumber(String amount) { if(amount==null || "".equals(amount)) { return ""; } Double doubleAmount = Double.valueOf(amount); double myAmount = doubleAmount.…
java decimalformatFloat sum = new Float(300); // always somehow calculated DecimalFormat df = new DecimalFormat("#.#"); String s = df.format(sum/3); // prints 100, I want 100.0 s = …
java decimalformatLet's look at the following statements in Java. System.out.println(new DecimalFormat("0").format(2.4)); //returns 2 System.out.println(new DecimalFormat("0").…
java decimalformatThe input stream I am parsing with Jackson contains latitude and longitude values such as here: { "name": "product 23", "latitude": "52,48264", "longitude": "13,31822" } …
java jackson json-deserialization decimalformat formatexceptionI am trying to keep two decimal places, even if then numbers are zeroes, using DecimalFormatter: DecimalFormat df = new DecimalFormat("#.00"); …
java decimalformatI have an XML file where the number are comma-separated <foo> <bar val="1,23"/> <bar val="4,56"/&…
xml xslt sum decimalformatIn my program I'm using the pattern #.## in DecimalFormat as shown below: DecimalFormat df = new DecimalFormat("#.##"); By mistake I added …
java decimalformatThe central problem is that I have a series of doubles that I need to log, each with varying number …
java double precision tostring decimalformatCan I disable rounding "feature" in DecimalFormat? For example: DecimalFormat f = new DecimalFormat(); f.parseObject("123456789012345.99"); Result is 1.2345678901234598E14 java version "1.6.0_21"
java rounding decimalformatHow would I convert the following code to C# DecimalFormat form String pattern = ""; for (int i = 0; i < nPlaces - …
c# java decimalformat