This one made me think:
class X;
void foo(X* p)
{
delete p;
}
How can we possibly delete p
if we do not even know whether X
has visible destructor? g++ 4.5.1 gives three warnings:
warning: possible problem detected in invocation of delete operator: warning: 'p' has incomplete type warning: forward declaration of 'struct X'
And then it says:
note: neither the destructor nor the class-specific operator delete will be called, even if they are declared when the class is defined.
Wow... are compilers required to diagnose this situation like g++ does? Or is it undefined behavior?
From the standard [expr.delete]:
If the object being deleted has incomplete class type at the point of deletion and the complete class has a non-trivial destructor or a deallocation function, the behavior is undefined.
So, it's UB if there's nontrivial stuff to do, and it's ok if there isn't. Warnings aren't neccessary for UB.