I have an array int arr[5]
that is passed to a function fillarr(int arr[])
:
int fillarr(int arr[])
{
for(...);
return arr;
}
In this case, your array variable arr
can actually also be treated as a pointer to the beginning of your array's block in memory, by an implicit conversion. This syntax that you're using:
int fillarr(int arr[])
Is kind of just syntactic sugar. You could really replace it with this and it would still work:
int fillarr(int* arr)
So in the same sense, what you want to return from your function is actually a pointer to the first element in the array:
int* fillarr(int arr[])
And you'll still be able to use it just like you would a normal array:
int main()
{
int y[10];
int *a = fillarr(y);
cout << a[0] << endl;
}