I am not a C programmer, so I am not that familiar with C-string but now I have to use a C library so here is a shortened version of my code to demonstrate my problem:
char** ReadLineImpl::my_completion () {
char* matches[1];
matches[0] = "add";
return matches;
}
I am getting this warning:
Warning - address of stack memory associated with local variable 'matches' returned
And my program does not seem to work properly (might be because of the above mentioned warning).
What does the warning imply? and will it cause any problems?
Variable char* matches[1];
is declared on stack, and it will be automatically released when current block goes out of the scope.
This means when you return matches
, memory reserved for matches
will be freed, and your pointer will point to something that you don't want to.
You can solve this in many ways, and some of them are:
Declare matches[1]
as static
: static char* matches[1];
- this
will allocate space for matches
in the static space and not on the stack (this may bite you if you
use it unappropriately, as all instances of my_completion
function
will share the same matches
variable).
Allocate space in the caller function and pass it to my_completion
function: my_completion(matches)
:
char* matches[1];
matches = my_completion(matches);
// ...
char** ReadLineImpl::my_completion (char** matches) {
matches[0] = "add";
return matches;
}
Allocate space in the called function on heap (using malloc
, calloc
, and friends) and pass the ownership to the caller function, which will have to deallocate this space when not needed anymore (using free
).