Groovy XmlSlurper: Find elements in XML structure

Robert Strauch picture Robert Strauch · Nov 30, 2011 · Viewed 21.2k times · Source

Let's say there is the following XML structure:

<Data>
    <DataFieldText>
        <DataFieldName>Field #1</DataFieldName>
        <DataFieldValue>1</DataFieldValue>
    </DataFieldText>
    <DataFieldText>
        <DataFieldName>Field #2</DataFieldName>
        <DataFieldValue>2</DataFieldValue>
    </DataFieldText>
    <DataFieldText>
        <DataFieldName>Field #3</DataFieldName>
        <DataFieldValue>3</DataFieldValue>
    </DataFieldText>
</Data>

Using Groovy's XmlSlurper I need to do the following:

Beginning from Data find that element which contains the value Field #1in the <DataFieldName> element. If found then get the value of the corresponding <DataFieldValue> which belongs to the same level.

Answer

socha23 picture socha23 · Nov 30, 2011

If DataFieldName is unique in a file:

println new XmlSlurper()
    .parseText(xml)
    .DataFieldText.find {it.DataFieldName == "Field #1"}
    .DataFieldValue.text()

If it is not, and you want to get an array with all matching DataFieldValues:

println new XmlSlurper()
    .parseText(xml)
    .DataFieldText.findAll {it.DataFieldName == "Field #1"}*.DataFieldValue*.text()