I am trying to print a value of type timeval. Actually I am able to print it, but I get the following warning:
Multiple markers at this line
The program compiles and it prints the values, but I would like to know if I am doing something wrong. Thanks.
printf("%ld.%6ld\n",usage.ru_stime);
printf("%ld.%6ld\n",usage.ru_utime);
where usage is of type
typedef struct{
struct timeval ru_utime; /* user time used */
struct timeval ru_stime; /* system time used */
long ru_maxrss; /* maximum resident set size */
long ru_ixrss; /* integral shared memory size */
long ru_idrss; /* integral unshared data size */
long ru_isrss; /* integral unshared stack size */
long ru_minflt; /* page reclaims */
long ru_majflt; /* page faults */
long ru_nswap; /* swaps */
long ru_inblock; /* block input operations */
long ru_oublock; /* block output operations */
long ru_msgsnd; /* messages sent */
long ru_msgrcv; /* messages received */
long ru_nsignals; /* signals received */
long ru_nvcsw; /* voluntary context switches */
long ru_nivcsw; /* involuntary context switches */
}rusage;
struct rusage usage;
In the GNU C Library, struct timeval
:
is declared in sys/time.h and has the following members:
long int tv_sec
This represents the number of whole seconds of elapsed time.
long int tv_usec
This is the rest of the elapsed time (a fraction of a second), represented as the number of microseconds. It is always less than one million.
So you will need to do
printf("%ld.%06ld\n", usage.ru_stime.tv_sec, usage.ru_stime.tv_usec);
to get a "nicely formatted" timestamp like 1.000123
.