I'm using NimbusLookAndFeel. With this look and feel JTable's cell background are alternatively white and light grey (it depends on the row number). Now, I'm writing some custom cell renderer implementing TableCellRenderer. I need to set the background of these renderers according to the position of the cell in the JTable.
public class MyCellRenderer extends JLabel implements TableCellRenderer{
@Override
public Component getTableCellRendererComponent(JTable table, Object value,
boolean isSelected, boolean hasFocus, int row, int column) {
Color bgColor = //need to retrieve the right cell background color
setBackground(bgColor);
return this;
}
}
How can I get such a Color value?
Technically, you can access the color via the UIManager
Color alternate = UIManager.getColor("Table.alternateRowColor");
Practically, I would not recommend to write renderers from scratch - there are many details to consider to get it right. Those details are handled f.i. in SwingX (biased me :-)
Expected you to do the logic yourself ;-). Here's a working snippet (assuming you want to color by row not by column, but changing that would be ... trivial):
TableCellRenderer renderer = new TableCellRenderer() {
JLabel label = new JLabel();
@Override
public Component getTableCellRendererComponent(JTable table,
Object value, boolean isSelected, boolean hasFocus,
int row, int column) {
label.setOpaque(true);
label.setText("" + value);
Color alternate = UIManager.getColor("Table.alternateRowColor");
if (row % 2 == 1) {
label.setBackground(alternate);
} else {
label.setBackground(Color.WHITE);
}
return label;
}
};
table.setDefaultRenderer(Object.class, renderer);