SwiftUI List Background color

Question

I am trying on setting a view background color to black with the following code

struct RuleList: View {[![enter image description here][1]][1]
private var presenter: ConfigurationPresenter?

@ObservedObject
private var viewModel: RowListViewModel

init(presenter: ConfigurationPresenter?, viewModel: RowListViewModel) {
    self.presenter = presenter
    self.viewModel = viewModel
}

var body: some View {
    List(viewModel.configurations) { configuration in
        RuleListRow(website: configuration.website).background(Color.black)
    }.background(Color.black)
}
}

struct RuleListRow: View {
var website: Website
@State private var websiteState = 0

var body: some View {
    VStack {
        Text(website.id).foregroundColor(.white)

        Picker(website.id, selection: $websiteState) {
            Text("Permis").tag(0)
            Text("Ascuns").tag(1)
            Text("Blocat").tag(2)
        }.pickerStyle(SegmentedPickerStyle()).background(Color.crimson)
    }.listRowBackground(Color.green)
}
}

The view is hosted in a mixed UIKit - SwiftUI storyboard, so this specific view is embed in a Hosting controller

class ConfigurationHostingController: UIHostingController<RuleList> {
private var presenter: ConfigurationPresenter = ConfigurationPresenter()

required init?(coder: NSCoder) {
    super.init(rootView: RuleList(presenter: presenter, viewModel: presenter.rowListViewModel))
}
}

I've tried any combination of .background, .listRowBackground(Color.black) and .colorMultiply(.black) I could think of, and the best I got is this

Answer 1

iOS 14

In iOS 14, you may consider using LazyVStack instead of list for this:

ScrollView {
    LazyVStack {
        ForEach((1...100), id: \.self) {
            Text("Placeholder \($0)")
        }
    }
    .background(Color.yellow)
}

Keep in mind that LazyVStack is lazy and doesn't render all rows all the time. So they are very performant and suggested by Apple itself in WWDC 2020.

---

iOS 13

All SwiftUI's Lists are backed by a UITableViewin iOS. so you need to change the background color of the tableView. But since Color and UIColor values are slightly different, you can get rid of the UIColor.

struct ContentView: View {
    
    init() {
        /// These could be anywhere before the list has loaded.
        UITableView.appearance().backgroundColor = .clear // tableview background
        UITableViewCell.appearance().backgroundColor = .clear // cell background
    }

    var body: some View {
        List {
            ,,,
        }
        .background(Color.yellow)
    }
}

Now you can use Any background (including all Colors) you want

Note that those top and bottom white areas are safe are and you can use .edgesIgnoringSafeArea() modifier to get rid of them.

⚠️ Important note!

Apple is on its way to deprecate all UIKit tricks that we are using in the SwiftUI (like tweaking the UIAppearance). So you may want to consider adapting your code to the latest iOS always