I have been trying to figure out how to programmatically find a square root of a number in Swift. I am looking for the simplest possible way to accomplish with as little code needed. I now this is probably fairly easy to accomplish, but can't figure out a way to do it.
Any input or suggestions would be greatly appreciated.
Thanks in advance
In Swift 3, the FloatingPoint
protocol appears to have a squareRoot()
method. Both Float
and Double
conform to the FloatingPoint
protocol. So:
let x = 4.0
let y = x.squareRoot()
is about as simple as it gets.
The underlying generated code should be a single x86 machine instruction, no jumping to the address of a function and then returning because this translates to an LLVM built-in in the intermediate code. So, this should be faster than invoking the C library's sqrt
function, which really is a function and not just a macro for assembly code.
In Swift 3, you do not need to import anything to make this work.