Why is my Swift loop failing with error "Can't form range with end < start"?

lagoon picture lagoon · Feb 22, 2015 · Viewed 27k times · Source

I have a for loop that checks if a number is a factor of a number, then checks if that factor is prime, and then it adds it to an array. Depending on the original number, I will get an error saying

fatal error: Can't form range with end < start

This happens almost every time, but for some numbers it works fine. The only numbers I have found to work with it are 9, 15, and 25.

Here is the code:

let num = 16 // or any Int
var primes = [Int]()

for i in 2...(num/2) {

    if ((num % i) == 0) {
        var isPrimeFactor = true

        for l in 2...i-1 {
            if ((i%l) == 0) {
                isPrimeFactor = false;
            }//end if
        }//end for

        if (isPrimeFactor == true) {
            primes.append(i)
        }//end if

    }//end if

}//end for

Answer

nahung89 picture nahung89 · Apr 26, 2016

Swift 5

If you need a loop with dynamic value-range, I suggest that using stride(to:by:) instead of ..< or ...

Basically ..< or ... will be crashed if start_index > end_index.

This will be crash:

let k = 5
for i in 10...k { print("i=\(i)") }
for i in 10..<k { print("i=\(i)") }

How to fix:

let k = 5
for i in stride(from: 10, through: k, by: 1) { print("i=\(i)") }
for i in stride(from: 10, to: k, by: 1) { print("i=\(i)") }

NOTE:

The code above won't print out anything, but it won't be crash when execution.

Also, if you want to stride from a higher number to a lower number then the by parameter needs to be changed to a negative number.

Reference: