Exit iteration of for loop Swift iOS

Alk picture Alk · Sep 11, 2016 · Viewed 39.7k times · Source

I have a function with a for loop inside of it:

func example() {
  // create tasks
  for link in links {
    let currIndex = links.indexOf(link)

    if let im = story_cache?.objectForKey(link) as? UIImage {
      if ((currIndex != nil) && (currIndex < content.count)) {
        if (content[currIndex!].resource_type == "image") {
          content[currIndex!].image = im
          return
        }
      }
    } else {
      if ((currIndex != nil) && (currIndex < content.count)) {
        if (content[currIndex!].resource_type == "video") {
          let paths = NSSearchPathForDirectoriesInDomains(.DocumentDirectory, .UserDomainMask, true)
          let documentsDirectory : NSString = paths[0]
          let appFile = documentsDirectory.stringByAppendingPathComponent(content[currIndex!].id! + ".mov")
          let local_URL = NSURL(fileURLWithPath: appFile)
          if let cached_URL = story_cache?.objectForKey(local_URL) as? NSURL {
            content[currIndex!].videoURL = cached_URL
            return
          }
        }
      }
    }

    let dltask = session.dataTaskWithURL(link, completionHandler: { (data, response, error) in  
      // MORE CODE.....
    })
  }
}

Basically what I wanna achieve is that if we reach any of the return statements the code finishes executing for this particular link in the loop, and the loop moves on to the next link. If NONE of the return statements are reached, I want the dltask to be executed. I could achieve this using a bunch of else statements but I think that would make the code quite messy. Am I doing this right with using return?

Answer

Shades picture Shades · Sep 11, 2016

You're looking for continue:

From Apple's Swift Book:

The continue statement tells a loop to stop what it is doing and start again at the beginning of the next iteration through the loop. It says “I am done with the current loop iteration” without leaving the loop altogether.

Just replace return with continue and it will go back up to the for loop and run it again with the next link.