I have a function with a for loop inside of it:
func example() {
// create tasks
for link in links {
let currIndex = links.indexOf(link)
if let im = story_cache?.objectForKey(link) as? UIImage {
if ((currIndex != nil) && (currIndex < content.count)) {
if (content[currIndex!].resource_type == "image") {
content[currIndex!].image = im
return
}
}
} else {
if ((currIndex != nil) && (currIndex < content.count)) {
if (content[currIndex!].resource_type == "video") {
let paths = NSSearchPathForDirectoriesInDomains(.DocumentDirectory, .UserDomainMask, true)
let documentsDirectory : NSString = paths[0]
let appFile = documentsDirectory.stringByAppendingPathComponent(content[currIndex!].id! + ".mov")
let local_URL = NSURL(fileURLWithPath: appFile)
if let cached_URL = story_cache?.objectForKey(local_URL) as? NSURL {
content[currIndex!].videoURL = cached_URL
return
}
}
}
}
let dltask = session.dataTaskWithURL(link, completionHandler: { (data, response, error) in
// MORE CODE.....
})
}
}
Basically what I wanna achieve is that if we reach any of the return
statements the code finishes executing for this particular link
in the loop, and the loop moves on to the next link. If NONE of the return statements are reached, I want the dltask
to be executed. I could achieve this using a bunch of else statements but I think that would make the code quite messy. Am I doing this right with using return
?
You're looking for continue
:
From Apple's Swift Book:
The continue statement tells a loop to stop what it is doing and start again at the beginning of the next iteration through the loop. It says “I am done with the current loop iteration” without leaving the loop altogether.
Just replace return
with continue
and it will go back up to the for
loop and run it again with the next link.