I'm trying to remove part of the path in a string. I have the path:
/path/to/file/drive/file/path/
I want to remove the first part /path/to/file/drive
and produce the output:
file/path/
Note: I have several paths in a while loop, with the same /path/to/file/drive
in all of them, but I'm just looking for the 'how to' on removing the desired string.
I found some examples, but I can't get them to work:
echo /path/to/file/drive/file/path/ | sed 's:/path/to/file/drive:\2:'
echo /path/to/file/drive/file/path/ | sed 's:/path/to/file/drive:2'
\2
being the second part of the string and I'm clearly doing something wrong...maybe there is an easier way?
If you wanted to remove a certain NUMBER of path components, you should use cut
with -d'/'
. For example, if path=/home/dude/some/deepish/dir
:
To remove the first two components:
# (Add 2 to the number of components to remove to get the value to pass to -f)
$ echo $path | cut -d'/' -f4-
some/deepish/dir
To keep the first two components:
$ echo $path | cut -d'/' -f-3
/home/dude
To remove the last two components (rev
reverses the string):
$ echo $path | rev | cut -d'/' -f4- | rev
/home/dude/some
To keep the last three components:
$ echo $path | rev | cut -d'/' -f-3 | rev
some/deepish/dir
Or, if you want to remove everything before a particular component, sed
would work:
$ echo $path | sed 's/.*\(some\)/\1/g'
some/deepish/dir
Or after a particular component:
$ echo $path | sed 's/\(dude\).*/\1/g'
/home/dude
It's even easier if you don't want to keep the component you're specifying:
$ echo $path | sed 's/some.*//g'
/home/dude/
And if you want to be consistent you can match the trailing slash too:
$ echo $path | sed 's/\/some.*//g'
/home/dude
Of course, if you're matching several slashes, you should switch the sed
delimiter:
$ echo $path | sed 's!/some.*!!g'
/home/dude
Note that these examples all use absolute paths, you'll have to play around to make them work with relative paths.