I've read that Scala'a case class
construct automatically generates a fitting equals
and hashCode
implementation. What does exactly the generated code look like?
As my professor used to say, only the code tells the truth! So just take a look at the code that is generated for:
case class A(i: Int, s: String)
We can instruct the Scala compiler to show us the generated code after the different phases, here after the typechecker:
% scalac -Xprint:typer test.scala
[[syntax trees at end of typer]]// Scala source: test.scala
package <empty> {
@serializable case class A extends java.lang.Object with ScalaObject with Product {
..
override def hashCode(): Int = ScalaRunTime.this._hashCode(A.this);
...
override def equals(x$1: Any): Boolean = A.this.eq(x$1).||(x$1 match {
case (i: Int,s: String)A((i$1 @ _), (s$1 @ _)) if i$1.==(i).&&(s$1.==(s)) => x$1.asInstanceOf[A].canEqual(A.this)
case _ => false
});
override def canEqual(x$1: Any): Boolean = x$1.$isInstanceOf[A]()
};
}
So you can see that the calculation of the hash code is delegated to ScalaRunTime._hashCode and the equality depends on the equality of the case class' members.