Why does this construction cause a Type Mismatch error in Scala?
for (first <- Some(1); second <- List(1,2,3)) yield (first,second)
<console>:6: error: type mismatch;
found : List[(Int, Int)]
required: Option[?]
for (first <- Some(1); second <- List(1,2,3)) yield (first,second)
If I switch the Some with the List it compiles fine:
for (first <- List(1,2,3); second <- Some(1)) yield (first,second)
res41: List[(Int, Int)] = List((1,1), (2,1), (3,1))
This also works fine:
for (first <- Some(1); second <- Some(2)) yield (first,second)
For comprehensions are converted into calls to the map
or flatMap
method. For example this one:
for(x <- List(1) ; y <- List(1,2,3)) yield (x,y)
becomes that:
List(1).flatMap(x => List(1,2,3).map(y => (x,y)))
Therefore, the first loop value (in this case, List(1)
) will receive the flatMap
method call. Since flatMap
on a List
returns another List
, the result of the for comprehension will of course be a List
. (This was new to me: For comprehensions don't always result in streams, not even necessarily in Seq
s.)
Now, take a look at how flatMap
is declared in Option
:
def flatMap [B] (f: (A) ⇒ Option[B]) : Option[B]
Keep this in mind. Let's see how the erroneous for comprehension (the one with Some(1)
) gets converted to a sequence of map calls:
Some(1).flatMap(x => List(1,2,3).map(y => (x, y)))
Now, it's easy to see that the parameter of the flatMap
call is something that returns a List
, but not an Option
, as required.
In order to fix the thing, you can do the following:
for(x <- Some(1).toSeq ; y <- List(1,2,3)) yield (x, y)
That compiles just fine. It is worth noting that Option
is not a subtype of Seq
, as is often assumed.