Is there a way to print a decimal as a percentage, so only the two digits after the period?
My decimals will always be between 1 and 0, so I suppose it would work to call number.round(2)
starting with the third character, but I can't find the syntax for that anywhere.
To clarify, I want the number to be stored as a full decimal, but printed as a percentage.
You are probably going to want to use the number_to_percentage
method. From the documentation, here are some examples of how to use it:
number_to_percentage(100) # => 100.000%
number_to_percentage("98") # => 98.000%
number_to_percentage(100, precision: 0) # => 100%
number_to_percentage(1000, delimiter: '.', separator: ',') # => 1.000,000%
number_to_percentage(302.24398923423, precision: 5) # => 302.24399%
number_to_percentage(1000, locale: :fr) # => 1 000,000%
number_to_percentage("98a") # => 98a%
number_to_percentage(100, format: "%n %") # => 100 %
Options:
:locale - Sets the locale to be used for formatting (defaults to current locale).
:precision - Sets the precision of the number (defaults to 3).
:significant - If true, precision will be the # of significant_digits. If false, the # of fractional digits (defaults to false).
:separator - Sets the separator between the fractional and integer digits (defaults to “.”).
:delimiter - Sets the thousands delimiter (defaults to “”).
:strip_insignificant_zeros - If true removes insignificant zeros after the decimal separator (defaults to false).
:format - Specifies the format of the percentage string The number field is %n (defaults to “%n%”).
Or you can write some ruby like the following:
class Numeric
def percent_of(n)
self.to_f / n.to_f * 100.0
end
end
p (1).percent_of(10) # => 10.0 (%)
p (200).percent_of(100) # => 200.0 (%)
p (0.5).percent_of(20) # => 2.5 (%)