Despite thoroughly reading the documentation, I'm rather confused about the meaning of the &
and *
symbol in Rust, and more generally about what is a Rust reference exactly.
In this example, it seems to be similar to a C++ reference (that is, an address that is automatically dereferenced when used):
fn main() {
let c: i32 = 5;
let rc = &c;
let next = rc + 1;
println!("{}", next); // 6
}
However, the following code works exactly the same:
fn main() {
let c: i32 = 5;
let rc = &c;
let next = *rc + 1;
println!("{}", next); // 6
}
Using *
to dereference a reference wouldn't be correct in C++. So I'd like to understand why this is correct in Rust.
My understanding so far, is that, inserting *
in front of a Rust reference dereferences it, but the *
is implicitly inserted anyway so you don't need to add it (while in C++, it's implicitly inserted and if you insert it you get a compilation error).
However, something like this doesn't compile:
fn main() {
let mut c: i32 = 5;
let mut next: i32 = 0;
{
let rc = &mut c;
next = rc + 1;
}
println!("{}", next);
}
error[E0369]: binary operation `+` cannot be applied to type `&mut i32`
--> src/main.rs:6:16
|
6 | next = rc + 1;
| ^^^^^^
|
= note: this is a reference to a type that `+` can be applied to; you need to dereference this variable once for this operation to work
= note: an implementation of `std::ops::Add` might be missing for `&mut i32`
But this works:
fn main() {
let mut c: i32 = 5;
let mut next: i32 = 0;
{
let rc = &mut c;
next = *rc + 1;
}
println!("{}", next); // 6
}
It seems that implicit dereferencing (a la C++) is correct for immutable references, but not for mutable references. Why is this?
Using * to dereference a reference wouldn't be correct in C++. So I'd like to understand why this is correct in Rust.
A reference in C++ is not the same as a reference in Rust. Rust's references are much closer (in usage, not in semantics) to C++'s pointers. With respect to memory representation, Rust's references often are just a single pointer, while C++'s references are supposed to be alternative names of the same object (and thus have no memory representation).
The difference between C++ pointers and Rust references is that Rust's references are never NULL
, never uninitialized and never dangling.
The Add
trait is implemented (see the bottom of the doc page) for the following pairs and all other numeric primitives:
&i32
+ i32
i32
+ &i32
&i32
+ &i32
This is just a convenience thing the std-lib developers implemented. The compiler can figure out that a &mut i32
can be used wherever a &i32
can be used, but that doesn't work (yet?) for generics, so the std-lib developers would need to also implement the Add
traits for the following combinations (and those for all primitives):
&mut i32
+ i32
i32
+ &mut i32
&mut i32
+ &mut i32
&mut i32
+ &i32
&i32
+ &mut i32
As you can see that can get quite out of hand. I'm sure that will go away in the future. Until then, note that it's rather rare to end up with a &mut i32
and trying to use it in a mathematical expression.