I have 2 lists, both of which contain same number of dictionaries. Each dictionary has a unique key. There is a match for each dictionary of the first list in the second list, that is a dictionary with a unique key exists in the other list. But the other elements of such 2 dictionaries may vary. For example:
list_1 = [
{
'unique_id': '001',
'key1': 'AAA',
'key2': 'BBB',
'key3': 'EEE'
},
{
'unique_id': '002',
'key1': 'AAA',
'key2': 'CCC',
'key3': 'FFF'
}
]
list_2 = [
{
'unique_id': '001',
'key1': 'AAA',
'key2': 'DDD',
'key3': 'EEE'
},
{
'unique_id': '002',
'key1': 'AAA',
'key2': 'CCC',
'key3': 'FFF'
}
]
I want to compare all elements of 2 matching dictionaries. If any of the elements are not equal, I want to print the none-equal elements.
Would you please help?
Assuming that the dicts line up like in your example input, you can use the zip()
function to get a list of associated pairs of dicts, then you can use any()
to check if there is a difference:
>>> list_1 = [{'unique_id':'001', 'key1':'AAA', 'key2':'BBB', 'key3':'EEE'},
{'unique_id':'002', 'key1':'AAA', 'key2':'CCC', 'key3':'FFF'}]
>>> list_2 = [{'unique_id':'001', 'key1':'AAA', 'key2':'DDD', 'key3':'EEE'},
{'unique_id':'002', 'key1':'AAA', 'key2':'CCC', 'key3':'FFF'}]
>>> pairs = zip(list_1, list_2)
>>> any(x != y for x, y in pairs)
True
Or to get the differing pairs:
>>> [(x, y) for x, y in pairs if x != y]
[({'key3': 'EEE', 'key2': 'BBB', 'key1': 'AAA', 'unique_id': '001'}, {'key3': 'EEE', 'key2': 'DDD', 'key1': 'AAA', 'unique_id': '001'})]
You can even get the keys which don't match for each pair:
>>> [[k for k in x if x[k] != y[k]] for x, y in pairs if x != y]
[['key2']]
Possibly together with the associated values:
>>> [[(k, x[k], y[k]) for k in x if x[k] != y[k]] for x, y in pairs if x != y]
[[('key2', 'BBB', 'DDD')]]
NOTE: In case you're input lists are not sorted yet, you can do that easily as well:
>>> from operator import itemgetter
>>> list_1, list_2 = [sorted(l, key=itemgetter('unique_id'))
for l in (list_1, list_2)]