What is the difference between int() and floor() in Python 3?

datah4ck3r picture datah4ck3r · Jun 24, 2015 · Viewed 34.3k times · Source

In Python 2, floor() returned a float value. Although not obvious to me, I found a few explanations clarifying why it may be useful to have floor() return float (for cases like float('inf') and float('nan')).

However, in Python 3, floor() returns integer (and returns overflow error for the special cases mentioned before).

So what is the difference, if any, between int() and floor() now?

Answer

Martijn Pieters picture Martijn Pieters · Jun 24, 2015

floor() rounds down. int() truncates. The difference is clear when you use negative numbers:

>>> import math
>>> math.floor(-3.5)
-4
>>> int(-3.5)
-3

Rounding down on negative numbers means that they move away from 0, truncating moves them closer to 0.

Putting it differently, the floor() is always going to be lower or equal to the original. int() is going to be closer to zero or equal.