Multilevel JSON diff in python

Question

Please link me to answer if this has already been answered, my problem is i want to get diff of multilevel json which is unordered.

x=json.loads('''[{"y":2,"x":1},{"x":3,"y":4}]''')
y=json.loads('''[{"x":1,"y":2},{"x":3,"y":4}]''')
z=json.loads('''[{"x":3,"y":4},{"x":1,"y":2}]''')

import json_tools as jt
import json_delta as jd


print jt.diff(y,z)
print jd.diff(y,z)
print y==z
print x==y

output is

[{'prev': 2, 'value': 4, 'replace': u'/0/y'}, {'prev': 1, 'value': 3, 'replace': u'/0/x'}, {'prev': 4, 'value': 2, 'replace': u'/1/y'}, {'prev': 3, 'value': 1, 'replace': u'/1/x'}]
[[[2], {u'y': 2, u'x': 1}], [[0]]]
False
True

my question is how can i get y and z to be equal or if there are actual differences depending on non-order of the JSON.

kind of unordered List of dictionaries but i am looking for something which is level-proof that is list/dict of dictionaries of list/dictionaries ...

Answer 1

Check out this python library jsondiff , that will help you to identify the diff's

import json

import jsondiff

json1 = json.loads(
    '{"isDynamic": false, "name": "", "value": "SID:<sid>", "description": "instance","argsOrder": 1,"isMultiSelect": false}')

json2 = json.loads(
    '{ "name": "", "value": "SID:<sid>","isDynamic": false, "description": "instance","argsOrder": 1,"isMultiSelect": false}')

res = jsondiff.diff(json1, json2)
if res:
    print("Diff found")
else:
    print("Same")