I'm uploading potentially large files to a web server. Currently I'm doing this:
import urllib2
f = open('somelargefile.zip','rb')
request = urllib2.Request(url,f.read())
request.add_header("Content-Type", "application/zip")
response = urllib2.urlopen(request)
However, this reads the entire file's contents into memory before posting it. How can I have it stream the file to the server?
Reading through the mailing list thread linked to by systempuntoout, I found a clue towards the solution.
The mmap
module allows you to open file that acts like a string. Parts of the file are loaded into memory on demand.
Here's the code I'm using now:
import urllib2
import mmap
# Open the file as a memory mapped string. Looks like a string, but
# actually accesses the file behind the scenes.
f = open('somelargefile.zip','rb')
mmapped_file_as_string = mmap.mmap(f.fileno(), 0, access=mmap.ACCESS_READ)
# Do the request
request = urllib2.Request(url, mmapped_file_as_string)
request.add_header("Content-Type", "application/zip")
response = urllib2.urlopen(request)
#close everything
mmapped_file_as_string.close()
f.close()