I familiar with the fact that I should set the HTTP_RPOXY environment variable to the proxy address.
Generally urllib works fine, the problem is dealing with urllib2.
>>> urllib2.urlopen("http://www.google.com").read()
returns
urllib2.URLError: <urlopen error [Errno 10061] No connection could be made because the target machine actively refused it>
or
urllib2.URLError: <urlopen error [Errno 11004] getaddrinfo failed>
I tried @Fenikso answer but I'm getting this error now:
URLError: <urlopen error [Errno 10060] A connection attempt failed because the
connected party did not properly respond after a period of time, or established
connection failed because connected host has failed to respond>
Any ideas?
You can do it even without the HTTP_PROXY environment variable. Try this sample:
import urllib2
proxy_support = urllib2.ProxyHandler({"http":"http://61.233.25.166:80"})
opener = urllib2.build_opener(proxy_support)
urllib2.install_opener(opener)
html = urllib2.urlopen("http://www.google.com").read()
print html
In your case it really seems that the proxy server is refusing the connection.
Something more to try:
import urllib2
#proxy = "61.233.25.166:80"
proxy = "YOUR_PROXY_GOES_HERE"
proxies = {"http":"http://%s" % proxy}
url = "http://www.google.com/search?q=test"
headers={'User-agent' : 'Mozilla/5.0'}
proxy_support = urllib2.ProxyHandler(proxies)
opener = urllib2.build_opener(proxy_support, urllib2.HTTPHandler(debuglevel=1))
urllib2.install_opener(opener)
req = urllib2.Request(url, None, headers)
html = urllib2.urlopen(req).read()
print html
Edit 2014:
This seems to be a popular question / answer. However today I would use third party requests
module instead.
For one request just do:
import requests
r = requests.get("http://www.google.com",
proxies={"http": "http://61.233.25.166:80"})
print(r.text)
For multiple requests use Session
object so you do not have to add proxies
parameter in all your requests:
import requests
s = requests.Session()
s.proxies = {"http": "http://61.233.25.166:80"}
r = s.get("http://www.google.com")
print(r.text)