Modify URL components in Python 2

Gareth Stockwell picture Gareth Stockwell · Jun 13, 2014 · Viewed 7.7k times · Source

Is there a cleaner way to modify some parts of a URL in Python 2?

For example

http://foo/bar -> http://foo/yah

At present, I'm doing this:

import urlparse

url = 'http://foo/bar'

# Modify path component of URL from 'bar' to 'yah'
# Use nasty convert-to-list hack due to urlparse.ParseResult being immutable
parts = list(urlparse.urlparse(url))
parts[2] = 'yah'

url = urlparse.urlunparse(parts)

Is there a cleaner solution?

Answer

Martijn Pieters picture Martijn Pieters · Jun 13, 2014

Unfortunately, the documentation is out of date; the results produced by urlparse.urlparse() (and urlparse.urlsplit()) use a collections.namedtuple()-produced class as a base.

Don't turn this namedtuple into a list, but make use of the utility method provided for just this task:

parts = urlparse.urlparse(url)
parts = parts._replace(path='yah')

url = parts.geturl()

The namedtuple._replace() method lets you create a new copy with specific elements replaced. The ParseResult.geturl() method then re-joins the parts into a url for you.

Demo:

>>> import urlparse
>>> url = 'http://foo/bar'
>>> parts = urlparse.urlparse(url)
>>> parts = parts._replace(path='yah')
>>> parts.geturl()
'http://foo/yah'

mgilson filed a bug report (with patch) to address the documentation issue.