My client socket would suspend in receving data if the rand number generated in Server socket less than 4. I need to set up time out mechanism to allow client socket detect there is "time out" and then it would continue send message. After I run the server socket and then the client socket, an error message showed below:
Traceback (most recent call last):
File "E:\Studying\Python workspace\Client\src\Client.py", line 34, in <module>
data , addr = client.recvfrom(1024)
socket.timeout: timed out
Server Socket:
import random
from socket import *
serverSocket = socket(AF_INET , SOCK_DGRAM)
serverSocket.bind(('', 15000))
while True:
rand = random.randint(0, 10)
message , address = serverSocket.recvfrom (1024)
message = message.upper()
print("received message: ", message)
print("echo to address: ", address)
print(rand)
if rand < 4:
continue
print("Sending message: ", message)
serverSocket.sendto(message, address)
Client Socket
import socket
UDP_IP = "127.0.0.1"
RPORT = 15000
MESSAGE = "ping"
print("UDP target IP: ", UDP_IP)
print("UDP target port: ", RPORT)
print("message going to send: ", MESSAGE)
client = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
i=1
while True:
try:
if(i<11):
client.sendto(MESSAGE.encode('utf_8'),(UDP_IP, RPORT))
print("sending message: ", MESSAGE)
print(i)
i=i+1
client.settimeout(2)
data , addr = client.recvfrom(1024)
print("received echo: ", data)
print("received at: " , addr )
finally:
print("closing socket")
client.close()
Well, settimeout() yields an exception. Try this:
while True:
try:
if(i<11):
client.sendto(MESSAGE.encode('utf_8'),(UDP_IP, RPORT))
print("sending message: ", MESSAGE)
print(i)
i=i+1
client.settimeout(2)
data , addr = client.recvfrom(1024)
print("received echo: ", data)
print("received at: " , addr )
except socket.timeout:
print("closing socket")
client.close()
If you want more information on socket.settimeout(), check this link: http://docs.python.org/2/library/socket.html#socket.timeout
Hope that helps!