I want to separate code in different class and put them to different files. However those class are dependent on each other.
main.py:
from lib import A, B
def main():
a = A()
b = B()
a.hello()
b.hello()
if __name__ == '__main__':
main()
lib/_init_.py:
from a import A
from b import B
lib/a.py:
import lib.B
class A():
def __init__(self):
print "A"
def hello(self):
print "hello A"
b = B()
lib/b.py:
import lib.A
class B():
def __init__(self):
print "B"
def hello(self):
print "hello B"
a = A()
Is it possible to do that in Python?
EDIT:
I get this error message:
pydev debugger: starting
Traceback (most recent call last):
File "eclipse-python/plugins/org.python.pydev_2.7.1.2012100913/pysrc/pydevd.py", line 1397, in <module>
debugger.run(setup['file'], None, None)
File "eclipse-python/plugins/org.python.pydev_2.7.1.2012100913/pysrc/pydevd.py", line 1090, in run
pydev_imports.execfile(file, globals, locals) #execute the script
File "main.py", line 2, in <module>
from lib import A, B
File "lib/__init__.py", line 1, in <module>
from a import A
File "lib/a.py", line 1, in <module>
import lib.B
ImportError: No module named B
Instead of importing the modules on top, you could import the other module within the hello function.
class B():
def __init__(self):
print "B"
def hello(self):
from lib import A
print "hello B"
a = A()