Finding a Eulerian Tour

james_dean picture james_dean · Sep 16, 2012 · Viewed 17k times · Source

I am trying to solve a problem on Udacity described as follows:

# Find Eulerian Tour
#
# Write a function that takes in a graph
# represented as a list of tuples
# and return a list of nodes that
# you would follow on an Eulerian Tour
#
# For example, if the input graph was
# [(1, 2), (2, 3), (3, 1)]
# A possible Eulerian tour would be [1, 2, 3, 1]

I came up with the following solution, which, while not as elegant as some of the recursive algorithms, does seem to work within my test case.

def find_eulerian_tour(graph):
    tour = []

    start_vertex = graph[0][0]
    tour.append(start_vertex)

    while len(graph) > 0:
        current_vertex = tour[len(tour) - 1]
        for edge in graph:
            if current_vertex in edge:
                if edge[0] == current_vertex:
                    current_vertex = edge[1]
                elif edge[1] == current_vertex:
                    current_vertex = edge[0]
                else:
                    # Edit to account for case no tour is possible
                    return False

                graph.remove(edge)
                tour.append(current_vertex)
                break
    return tour

graph = [(1, 2), (2, 3), (3, 1)]
print find_eulerian_tour(graph)

>> [1, 2, 3, 1]

However, when submitting this, I get rejected by the grader. I am doing something wrong? I can't see any errors.

Answer

Reinstate Monica picture Reinstate Monica · Sep 17, 2012

Here's a valid case where your algorithm fails:

graph = [(1, 2), (2, 3), (3, 1), (3, 4), (4, 3)]

Use the power of print to find out what happens to graph and current_vertex.

Another hint: Move the else down so that it belongs to the for and is executed when the for loop is not broken. As it is now, it can never be executed. After that correction, the algorithm still fails, of course.

The algorithm still fails, of course.

The algorithm still fails, of course.

Please, don't comment stating that the code doesn't work. It doesn't. The algorithm still fails, even if the code below does what the OP had in mind. The point was to show that the OP's algorithm is wrong, which the OP couldn't determine. For that, a correct implementation of OP's algorithm is needed (see below). A correct implementation of a wrong algorithm is still not a correct solution.

I'm sorry to make this answer worse by writing all these lengthy explanations, but people continue to complain that the code doesn't work (of course, the point was to show that it is wrong). They also downvote this answer, probably because they expect to be able to copy the code as a solution. But this is not the point, the point is to show to the OP that there is an error in his algorithm.

The code below does not find eulerian tours. Look elsewhere to copy code for passing your assingments!

def find_eulerian_tour(graph):
    tour = []

    current_vertex = graph[0][0]
    tour.append(current_vertex)

    while len(graph) > 0:
        print(graph, current_vertex)
        for edge in graph:
            if current_vertex in edge:
                if edge[0] == current_vertex:
                    current_vertex = edge[1]
                else:
                    current_vertex = edge[0]

                graph.remove(edge)
                tour.append(current_vertex)
                break
        else:
            # Edit to account for case no tour is possible
            return False
    return tour

graph = [(1, 2), (2, 3), (3, 1), (3, 4), (4, 3)]
print(find_eulerian_tour(graph))

Output:

[(1, 2), (2, 3), (3, 1), (3, 4), (4, 3)] 1
[(2, 3), (3, 1), (3, 4), (4, 3)] 2
[(3, 1), (3, 4), (4, 3)] 3
[(3, 4), (4, 3)] 1
False