I would like to select the top entries in a Pandas dataframe base on the entries of a specific column by using df_selected = df_targets.head(N)
.
Each entry has a target
value (by order of importance):
Likely Supporter, GOTV, Persuasion, Persuasion+GOTV
Unfortunately if I do
df_targets = df_targets.sort("target")
the ordering will be alphabetical (GOTV
,Likely Supporter
, ...).
I was hoping for a keyword like list_ordering
as in:
my_list = ["Likely Supporter", "GOTV", "Persuasion", "Persuasion+GOTV"]
df_targets = df_targets.sort("target", list_ordering=my_list)
To deal with this issue I create a dictionary:
dict_targets = OrderedDict()
dict_targets["Likely Supporter"] = "0 Likely Supporter"
dict_targets["GOTV"] = "1 GOTV"
dict_targets["Persuasion"] = "2 Persuasion"
dict_targets["Persuasion+GOTV"] = "3 Persuasion+GOTV"
, but it seems like a non-pythonic approach.
Suggestions would be much appreciated!
I think you need Categorical
with parameter ordered=True
and then sorting by sort_values
works very nice:
If check documentation of Categorical
:
Ordered Categoricals can be sorted according to the custom order of the categories and can have a min and max value.
import pandas as pd
df = pd.DataFrame({'a': ['GOTV', 'Persuasion', 'Likely Supporter',
'GOTV', 'Persuasion', 'Persuasion+GOTV']})
df.a = pd.Categorical(df.a,
categories=["Likely Supporter","GOTV","Persuasion","Persuasion+GOTV"],
ordered=True)
print (df)
a
0 GOTV
1 Persuasion
2 Likely Supporter
3 GOTV
4 Persuasion
5 Persuasion+GOTV
print (df.a)
0 GOTV
1 Persuasion
2 Likely Supporter
3 GOTV
4 Persuasion
5 Persuasion+GOTV
Name: a, dtype: category
Categories (4, object): [Likely Supporter < GOTV < Persuasion < Persuasion+GOTV]
df.sort_values('a', inplace=True)
print (df)
a
2 Likely Supporter
0 GOTV
3 GOTV
1 Persuasion
4 Persuasion
5 Persuasion+GOTV