Slicing a Python OrderedDict

user5035297 picture user5035297 · Jun 22, 2015 · Viewed 9.9k times · Source

In my code I frequently need to take a subset range of keys+values from a Python OrderedDict (from collections package). Slicing doesn't work (throws TypeError: unhashable type) and the alternative, iterating, is cumbersome:

from collections import OrderedDict

o = OrderedDict([('a', 1), ('b', 2), ('c', 3), ('d', 4)])

# want to do:
# x = o[1:3]
# need to do:
x = OrderedDict()
for idx, key in enumerate(o):
    if 1 <= idx < 3:
        x[key] = o[key]

Is there a better way to get this done?

Answer

Jimmy C picture Jimmy C · Jun 22, 2015

You can use the itertools.islice function, which takes an iterable and outputs the stop first elements. This is beneficial since iterables don't support the common slicing method, and you won't need to create the whole items list from the OrderedDict.

from collections import OrderedDict
from itertools import islice
o = OrderedDict([('a', 1), ('b', 2), ('c', 3), ('d', 4)])
sliced = islice(o.iteritems(), 3)  # o.iteritems() is o.items() in Python 3
sliced_o = OrderedDict(sliced)