Displaying a drupal page without the template around it in Drupal 7
I'd like to render the contents of a "basic page" in drupal. Something like this question: displaying a Drupal view without a page template around it but for Drupal 7.
My attempt almost works:
function mytheme_preprocess_page(&$variables, $hook) {
if ( isset($_GET['ajax']) && $_GET['ajax'] == 1 ) {
$variables['theme_hook_suggestions'][] = 'page__ajax';
}
}
And have a file named page--ajax.tpl.php in the same directory where template.php lives:
<?php print $page['content']; ?>
The problem is that it still renders the menu and my two custom blocks from the sidebar. I only want the page content. What should I change?
Answer
You are almost there. The only thing you need is to add a custom HTML wrapper template.
- Add a function to
template.php:
function THEMENAME_preprocess_html(&$variables, $hook) {
if ( isset($_GET['ajax']) && $_GET['ajax'] == 1 ) {
$variables['theme_hook_suggestions'][] = 'html__ajax';
}
}
- Create a file named
html--ajax.tpl.php
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML+RDFa 1.0//EN"
"http://www.w3.org/MarkUp/DTD/xhtml-rdfa-1.dtd">`
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<?php print $styles; ?>
<?php print $scripts; ?>
</head>
<body class="<?php print $classes; ?>">
<?php print $page_top; ?>
<?php print $page; ?>
<?php print $page_bottom; ?>
</body>
</html>
- Flush all caches. That's all.