preg_replace_all() related issue

php function replace bbcode
Aristona picture Aristona · Jan 4, 2012 · Viewed 7.1k times · Source

I am currently making a BBCode class for my website. I need to do the following.

function bbCode([skill]Q[/skill]_________[skill]Q[/skill]_________[skill]Q[/skill]);

bbCode function has to replace all Q's between [skill] and [/skill] tags, and replace it with $skillArray['Q'] value. ($skillArray is character dependant.)

How can I do this?

A little clearer version is:

  1. For example you're on a page of "Orc" character.
  2. [skill]Q[/skill] tag should get "Orc's Q skill name" automatically.
  3. For example you're on a page of "Hunter" character.
  4. [skill]Q[/skill] tag should get "Hunter's Q skill name" automatically.

Ps. Don't want to use explode.

Answer

Ashley Banks picture Ashley Banks · Jan 4, 2012

Assuming the tags you want to be replaced are within some form of template, you could use file_get_contents and then loop through the tags you want to replace with the desired values, for example:

$file = file_get_contents ( 'yourfile.php' );

$skillArray = array ( 'Q' => 'Hunter name' );

foreach ( $skillArray as $key => $val )
{
    $file = str_replace ( '[skill]' . $key . '[\skill]', $val, $file );
}

Thats just a completely rough example, but if I'm understanding what you are trying to do; that should be along the right lines....

Related questions

Deprecated: mysql_connect()

I am getting this warning, but the program still runs correctly. The MySQL code is showing me a message in PHP: Deprecated: mysql_connect(): The mysql extension is deprecated and will be removed in the future: use mysqli or PDO …

Read More
PHP Fatal error: Using $this when not in object context

I've got a problem: I'm writing a new WebApp without a Framework. In my index.php I'm using: require_once('load.php'); And in load.php I'm using require_once('class.php'); to load my class.php. In my class.…

Read More
PHP append one array to another (not array_push or +)

How to append one array to another without comparing their keys? $a = array( 'a', 'b' ); $b = array( 'c', 'd' ); At the end it should be: Array( [0]=>a [1]=>b [2]=>c [3]=>d ) If I use something like [] or …

Read More