How to pass arguments to an included file?
I'm trying to make the whole <head> section its own include file. One drawback is the title and description and keyword will be the same; I can't figure out how to pass arguments to the include file.
So here is the code:
index.php
<?php include("header.php?header=aaaaaaaaaaaaaaaaaaaaa"); ?>
<body>
.....
..
.
header.php
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<link rel="shortcut icon" href="favicon.ico">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<meta name="Keywords" content=" <?php $_GET["header"]?> " >
<meta name="Description" content=" <?php $_GET["header"]?> " >
<title> <?php $_GET["header"]?> </title>
<link rel="stylesheet" type="text/css" href="reset.css" />
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.3/jquery.min.js"></script>
</head>
Obviously this doesn't work; how can I pass arguments to an included file?
Answer
Include has the scope of the line it's called from.
If you don't want to create new global variables, you can wrap include() with a function:
function includeHeader($title) {
include("inc/header.php");
}
$title will be defined in the included code whenever you call includeHeader with a value, for example includeHeader('My Fancy Title').
If you want to pass more than one variable you can always pass an array instead of a string.
Let's create a generic function:
function includeFile($file, $variables) {
include($file);
}
Voila!
Using extract makes it even neater:
function includeFileWithVariables($fileName, $variables) {
extract($variables);
include($fileName);
}
Now you can do:
includeFileWithVariables("header.php", array(
'keywords'=> "Potato, Tomato, Toothpaste",
'title'=> "Hello World"
));
Knowing that it will cause variables $keywords and $title to be defined in the scope of the included code.