In PHP you can call a function with no arguments passed in so long as the arguments have default values like this:
function test($t1 ='test1',$t2 ='test2',$t3 ='test3')
{
echo "$t1, $t2, $t3";
}
test();
However, let's just say I want the last one to be different but the first two parameters should use their default values. The only way I can think of is by doing this with no success:
test('test1','test2','hi i am different');
I tried this:
test(,,'hi i am different');
test(default,default,'hi i am different');
Is there clean, valid way to do this?
Use arrays :
function test($options = array()) {
$defaults = array(
't1' => 'test1',
't2' => 'test2',
't3' => 'test3',
);
$options = array_merge($defauts, $options);
extract($options);
echo "$t1, $t2, $t3";
}
Call your function this way :
test(array('t3' => 'hi, i am different'));