Dynamically generate classes at runtime in php?

Question

Here's what I want to do:

$clsName = substr(md5(rand()),0,10); //generate a random name
$cls = new $clsName(); //create a new instance

function __autoload($class_name)
{
  //define that instance dynamically
}

Obviously this isn't what I'm actually doing, but basically I have unknown names for a class and based on the name, I want to generate the class with certain properties etc.

I've tried using eval() but it is giving me fits over private and $this-> references...

//edit

Ok, obviously my short and sweet "here's what I want to do" caused massive strife and consternation amongst those who may be able to provide answers. In the hope of getting an actual answer I'll be more detailed.

I have a validation framework using code hints on the site I maintain. Each function has two definitions

function DoSomething($param, $param2){
   //code
}
function DoSomething_Validate(vInteger $param, vFloat $param2){
   //return what to do if validation fails
}

I'm looking to add a validator for primary keys in my database. I don't want to create a separate class for EVERY table (203). So my plan was to do something like

function DoSomething_Validate(vPrimaryKey_Products $id){ }

Where the __autoload would generate a subclass of vPrimaryKey and set the table parameter to Products.

Happy now?

Answer 1

its funny, actually this is one of the few things where eval doesnt seem such a bad idea.

as long as you can ensure that no user input will ever enter the eval.

you still have downsides like when your using a bytecode cache that code wont be cached etc etc. but the security issues of eval are pretty much related to having user inputy in the eval, or to ending up in the wrong scope.

if you know what you are doing, eval will help you with this.

That said, in my opinion you are much better off when you no rely on type-hinting for your validation, but you have one function

DoSomething_Validate($id)
{ 
   // get_class($id) and other validation foo here
}