I want to know how to fetch single row from Oracle in PHP?
Chedck my script-: I want to fetch single row from ITEM_INFO table & compare that values with variables $sku & $code...Logic I applied which works in Mysql but not working in Oracle...
Each time $sku & $code contains diff. values so I just need to compare them with ITEM_INFO table & if it's matches then update the flag for the same...
$query_fetch = "SELECT ITEM_NAME,SITE_CODE FROM app.ITEM_INFO WHERE ITEM_FLAG = 'N'";
$stmt = oci_parse($conn,$query_fetch);
oci_execute($stmt);
while(($row = oci_fetch_array($stmt, OCI_BOTH)))
{
$ITEM_NAME = ($row["ITEM_NAME"]);
$SITE_CODE = ($row["SITE_CODE"]);
if(($ITEM_NAME === $sku) && ($SITE_CODE === $code))
{
$query_ora_update = "UPDATE app.ITEM_INFO SET ITEM_FLAG= 'Y', LAST_UPDATE_DATE = sysdate WHERE ITEM_NAME = '$sku' AND SITE_CODE = '$code' AND ITEM_FLAG = 'N' ";
$parse_result = oci_parse($conn,$query_ora_update);
$result = oci_execute($parse_result);
oci_commit($conn);
oci_close($conn);
}
}
plz guide me...
Basically, you just have to remove the while
loop.
Here's a rewrite of your code applying that change (+ you use too many parenthesis, decreasing your code readability + you should use SQL binding to avoid injection):
$query_ora_update = "UPDATE app.ITEM_INFO SET ITEM_FLAG= 'Y', LAST_UPDATE_DATE = sysdate WHERE ITEM_FLAG = 'N'";
$parse_result = oci_parse($conn, $query_ora_update);
$result = oci_execute($parse_result);
oci_commit($conn);
oci_close($conn);