I know that passing a scalar to a sub is actually passing the reference, but since I am new to perl I still did the following test:
#!/usr/bin/perl
$i = 2;
subr(\$i);
sub subr{
print $_[0]."\n";
print $$_[0]."\n";
}
I thought the first line is going to print an address and the second line is going to give be back the number, but the second one is a blank line. I was pointed by someone one else to do this: ${$_[0]}
and it prints the number. But she didn't know the reason why without {} it is not working and why it is working with {}. So what has happened?
It's because your second print statement is equivalent to doing this...
my $x = $$_; print $x[0];
When what you want is
my $x = $_[0]; print $$x;
In other words, the de-referencing occurs before the array subscript is evaluated.
When you add those curl-wurlies, it tells perl how to interpret the expression as you want it; it will evaluate $_[0]
first, and then de-reference to get the value.