What does gcc's ffast-math actually do?
I understand gcc's --ffast-math flag can greatly increase speed for float ops, and goes outside of IEEE standards, but I can't seem to find information on what is really happening when it's on. Can anyone please explain some of the details and maybe give a clear example of how something would change if the flag was on or off?
I did try digging through S.O. for similar questions but couldn't find anything explaining the workings of ffast-math.
Answer
-ffast-math does a lot more than just break strict IEEE compliance.
First of all, of course, it does break strict IEEE compliance, allowing e.g. the reordering of instructions to something which is mathematically the same (ideally) but not exactly the same in floating point.
Second, it disables setting errno after single-instruction math functions, which means avoiding a write to a thread-local variable (this can make a 100% difference for those functions on some architectures).
Third, it makes the assumption that all math is finite, which means that no checks for NaN (or zero) are made in place where they would have detrimental effects. It is simply assumed that this isn't going to happen.
Fourth, it enables reciprocal approximations for division and reciprocal square root.
Further, it disables signed zero (code assumes signed zero does not exist, even if the target supports it) and rounding math, which enables among other things constant folding at compile-time.
Last, it generates code that assumes that no hardware interrupts can happen due to signalling/trapping math (that is, if these cannot be disabled on the target architecture and consequently do happen, they will not be handled).