How to calculate "modular multiplicative inverse" when the denominator is not co-prime with m?

Lazer picture Lazer · Oct 5, 2009 · Viewed 12.3k times · Source

I need to calculate (a/b) mod m where a and b are very large numbers.

What I am trying to do is to calculate (a mod m) * (x mod m), where x is the modular inverse of b.

I tried using Extended Euclidean algorithm, but what to do when b and m are not co-prime? It is specifically mentioned that b and m need to be co-prime.

I tried using the code here, and realized that for example: 3 * x mod 12 is not at all possible for any value of x, it does not exist!

What should I do? Can the algorithm be modified somehow?

Answer

Keith Randall picture Keith Randall · Oct 5, 2009

Yep, you are in trouble. x has no solution in b*x = 1 mod m if b and m have a common divisor. Similarly, in your original problem a/b = y mod m, you are looking for y such that a=by mod m. If a is divisible by gcd(b,m), then you can divide out by that factor and solve for y. If not, then there is no y that can solve the equation (i.e. a/b mod m is not defined).