correct glsl affine texture mapping

velkyel picture velkyel · Sep 13, 2012 · Viewed 7.7k times · Source

i'm trying to code correct 2D affine texture mapping in GLSL.

Explanation:

...NONE of this images is correct for my purposes. Right (labeled Correct) has perspective correction which i do not want. So this: Getting to know the Q texture coordinate solution (without further improvements) is not what I'm looking for.

I'd like to simply "stretch" texture inside quadrilateral, something like this:

enter image description here

but composed from two triangles. Any advice (GLSL) please?

Answer

Jessy picture Jessy · Sep 15, 2012

This works well as long as you have a trapezoid, and its parallel edges are aligned with one of the local axes. I recommend playing around with my Unity package.

GLSL:

varying vec2 shiftedPosition, width_height;

#ifdef VERTEX
void main() {
    gl_Position = gl_ModelViewProjectionMatrix * gl_Vertex;
    shiftedPosition = gl_MultiTexCoord0.xy; // left and bottom edges zeroed.
    width_height = gl_MultiTexCoord1.xy;
}
#endif

#ifdef FRAGMENT
uniform sampler2D _MainTex;
void main() {
    gl_FragColor = texture2D(_MainTex, shiftedPosition / width_height);
}
#endif

C#:

// Zero out the left and bottom edges, 
// leaving a right trapezoid with two sides on the axes and a vertex at the origin.
var shiftedPositions = new Vector2[] {
    Vector2.zero,
    new Vector2(0, vertices[1].y - vertices[0].y),
    new Vector2(vertices[2].x - vertices[1].x, vertices[2].y - vertices[3].y),
    new Vector2(vertices[3].x - vertices[0].x, 0)
};
mesh.uv = shiftedPositions;

var widths_heights = new Vector2[4];
widths_heights[0].x = widths_heights[3].x = shiftedPositions[3].x;
widths_heights[1].x = widths_heights[2].x = shiftedPositions[2].x;
widths_heights[0].y = widths_heights[1].y = shiftedPositions[1].y;
widths_heights[2].y = widths_heights[3].y = shiftedPositions[2].y;
mesh.uv2 = widths_heights;