Multiple option arguments using getopts (bash)

Question

I am trying to process command line arguments using getopts in bash. One of the requirements is for the processing of an arbitrary number of option arguments (without the use of quotes).

1st example (only grabs the 1st argument)

madcap:~/projects$ ./getoptz.sh -s a b c
-s was triggered
Argument: a

2nd example (I want it to behave like this but without needing to quote the argument"

madcap:~/projects$ ./getoptz.sh -s "a b c"
-s was triggered
Argument: a b c

Is there a way to do this?

Here's the code I have now:

#!/bin/bash
while getopts ":s:" opt; do
    case $opt in
    s) echo "-s was triggered" >&2
       args="$OPTARG"
       echo "Argument: $args"
       ;;
   \?) echo "Invalid option: -$OPTARG" >&2
       ;;
    :) echo "Option -$OPTARG requires an argument." >&2
       exit 1
       ;;
    esac
done

Answer 1

I think what you want is to get a list of values from a single option. For that, you can repeat the option as many times as needed, and add it's argument to an array.

#!/bin/bash

while getopts "m:" opt; do
    case $opt in
        m) multi+=("$OPTARG");;
        #...
    esac
done
shift $((OPTIND -1))

echo "The first value of the array 'multi' is '$multi'"
echo "The whole list of values is '${multi[@]}'"

echo "Or:"

for val in "${multi[@]}"; do
    echo " - $val"
done

The output would be:

$ /tmp/t
The first value of the array 'multi' is ''
The whole list of values is ''
Or:

$ /tmp/t -m "one arg with spaces"
The first value of the array 'multi' is 'one arg with spaces'
The whole list of values is 'one arg with spaces'
Or:
 - one arg with spaces

$ /tmp/t -m one -m "second argument" -m three
The first value of the array 'multi' is 'one'
The whole list of values is 'one second argument three'
Or:
 - one
 - second argument
 - three