Filter multiple <ul> lists with jQuery

Dante picture Dante · Feb 21, 2012 · Viewed 25.2k times · Source

I have multiple lists on one page (multiple categories of products) like this:

<h3>Category 1</h3>
<ul id="category1">
    <li>item1</li>
    <li>item2</li>
    <li>item3</li>
</ul>
<h3>Category 2</h3>
<ul id="category2">
    <li>item27</li>
    <li>item28</li>
</ul>

The amount of lists is variable.

I would like a filter like on the demo page here http://static.railstips.org/orderedlist/demos/quicksilverjs/jquery.html.

But it should search over the different lists.

If the user searches for "2" then the result should be:

<h3>Category 1</h3>
<ul id="category1">
    <li>item2</li>
</ul>
<h3>Category 2</h3>
<ul id="category2">
    <li>item27</li>
    <li>item28</li>
</ul>

If he searches for "1" then it should be (don't show h3 title for list where there are no results):

<h3>Category 1</h3>
<ul id="category1">
    <li>item1</li>
</ul>

Can someone help me?

Thanks in advance!

Answer

Johan picture Johan · Feb 21, 2012

How about something like this:

HTML

<input type="text" />

<ul id="category1">
    <li>item1</li>
    <li>item2</li>
    <li>item3</li>
</ul>
<ul>
    <li>item27</li>
    <li>item28</li>
</ul>

JS

$(function(){

    $('input[type="text"]').keyup(function(){

        var searchText = $(this).val();

        $('ul > li').each(function(){

            var currentLiText = $(this).text(),
                showCurrentLi = currentLiText.indexOf(searchText) !== -1;

            $(this).toggle(showCurrentLi);

        });     
    });

});

http://jsfiddle.net/EFTZR/146/

Another solution using filter(), which is mentioned below:

$('input[type="text"]').keyup(function(){

    var that = this, $allListElements = $('ul > li');

    var $matchingListElements = $allListElements.filter(function(i, li){
        var listItemText = $(li).text().toUpperCase(), 
            searchText = that.value.toUpperCase();
        return ~listItemText.indexOf(searchText);
    });

    $allListElements.hide();
    $matchingListElements.show();

});

http://jsfiddle.net/EFTZR/441/