Where should I declare functions that are called inside a useEffect() hook?

cbdeveloper picture cbdeveloper · Jul 2, 2019 · Viewed 10.7k times · Source

So I have the following situation when using a useEffect that calls a functions that depends on state.

Example:

// INSIDE APP COMPONENT

const [someState, setSomeState] = React.useState(0);
const [someTrigger, setSomeTrigger] = React.useState(false);

function someFunction() {
  return someState + 1;  
}

React.useEffect(() => {

  const newState = someFunction();  // 'someFunction' IS BEING CALLED HERE
  setSomeState(newState);

},[someTrigger])

QUESTIONS:

In this case, should I declare someFunction inside the useEffect() or is it safe to keep it outside (but inside component's body)?

I could add it to the dependency array, but it will hurt the redability of my code, since I want to focus on the trigger.

Since the useEffect() will run after a fresh render, is it safe to assume that it will have fresh copies of the functions that I'm calling inside of it?

Is there a basic rule of when you should declare functions inside the useEffect hook or when is it mandatory that you add it to the dependency array?

EDIT: Note that it's necessary that the useEffect has fresh copies of those functions, since those functions need to access some fresh up-to-date state variable.

NOTE:

This code triggers the following eslint warning on CodeSandbox. Although it works just fine.

React Hook React.useEffect has a missing dependency: 'someFunction'. Either include it or remove the dependency array. (react-hooks/exhaustive-deps)eslint

REAL CASE SCENARIO:

This is a simplified example. In my real case, this is a product search page with filters components. So when I click on a filter to activate it (let's say, price <= 50), I'm triggering a useEffect() that is "listening" for the activePriceFilters state variable. That effect then calls a function (someFunction in the example) that will calculate the filteredList and will set the new productList state with the new filteredList.

SNIPPET

Answer

Shubham Khatri picture Shubham Khatri · Jul 2, 2019

A decision to define a function within or outside of useEffect depends on where all the functions is called.

If your function is called only from within the useEffect then it makes sense to define it within the useEffect.

However is the same function is being called from within useEffect as well as other event handlers or other effects, you need to define it outside of useEffect

PS. in your case you are just updating the state for which you needn't define a separate function

function App() {
  
  const [someState, setSomeState] = React.useState(0);
  const [someTrigger, setSomeTrigger] = React.useState(false);
  

  React.useEffect(() => {
    setSomeState(oldState => oldState + 1);
  
  },[someTrigger])
  
  return(
    <React.Fragment>
      <div>I am App</div>
      <div>My state: {someState}</div>
      <button onClick={()=>setSomeTrigger((prevState) => !prevState)}>Click</button>
    </React.Fragment>
  );
}

ReactDOM.render(<App/>, document.getElementById('root'));
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/16.8.3/umd/react.production.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react-dom/16.8.3/umd/react-dom.production.min.js"></script>
<div id="root"/>

As far as you scenario is concerned, you would write it like

useEffect(() => {
    const calcVal = (oldState) => {
         // calculate previous state based on oldState
    }

    setSomeState(calcVal);
}, [activePriceFilters])