spread syntax vs slice method

iRohitBhatia picture iRohitBhatia · Jul 4, 2018 · Viewed 9.2k times · Source

I was trying to understand what is the difference between spread syntax vs slice method in the following approach.

suppose I want to make an actual copy of an array, I can probably easily do it using spread syntax

var fruits = ["Banana", "Chips" , "Orange", "Lemon", "Apple", "Mango"]
var newCitrus = [...fruits]

If I console.log this

["Banana", "Chips", "Orange", "Lemon", "Apple", "Mango"] 

but I can also create a copy of an array using the slice method. Considering the same array above, if I do something like this...

var citrus = fruits.slice(0);

and then console log it, it will give me exactly the same array which I would've got through spread syntax

["Banana", "Chips", "Orange", "Lemon", "Apple", "Mango"] 

Since both of them takes about the same time to code/write, What is the difference here? which approach should I usually choose?

Answer

Bartosz Gościński picture Bartosz Gościński · Sep 12, 2018

Performance aside slice is just a function on Array.prototype so it will work only for arrays. Spread syntax on the other hand will work for any iterable (object which satisfy iterable protocol) so it will work out of the box on any String, Array, TypedArray, Map and Set. You can also easily create custom iterables.

There is also a difference when it comes to sliceing and spreading arrays with holes (sparse arrays). As you can see below, slice will preserve sparseness while spread will fill holes with undefined.

Array(3)         // produces sparse array: [empty × 3]
Array(3).slice() // produces [empty × 3]
[...Array(3)]    // produces [undefined, undefined, undefined]

Spread syntax can also be used to make shallow clones of objects:

const obj = { foo: 'bar', baz: 42 };
const clone = { ...obj1 };
obj.foo === clone.foo // true
obj.baz === clone.baz // true
obj === clone         // false (references are different)