How to run a npm script command from inside a gulp task?
package.json
"scripts":
{
"tsc": "tsc -w"
}
gulpfile.js
gulp.task('compile:app', function(){
return gulp.src('src/**/*.ts')
.pipe(/*npm run tsc*/)
.pipe(gulp.dest('./dist'))
.pipe(connect.reload());
});
I want to do this because running npm run tsc
does not give me any error but if I use gulp-typescript
to compile .ts
then I get bunch of errors.
You can get the equivalent using gulp-typescript
var gulp = require('gulp');
var ts = require('gulp-typescript');
gulp.task('default', function () {
var tsProject = ts.createProject('tsconfig.json');
var result = tsProject.src().pipe(ts(tsProject));
return result.js.pipe(gulp.dest('release'));
});
gulp.task('watch', ['default'], function() {
gulp.watch('src/*.ts', ['default']);
});
Then on your package.json
"scripts": {
"gulp": "gulp",
"gulp-watch": "gulp watch"
}
Then run
npm run gulp-watch
Alternatively using shell
var gulp = require('gulp');
var shell = require('gulp-shell');
gulp.task('default', function () {
return gulp.src('src/**/*.ts')
.pipe(shell('npm run tsc'))
.pipe(gulp.dest('./dist'))
.pipe(connect.reload());
});
gulp-shell
has been blacklisted you can see why here
Another alternative would be setting up webpack
.