How to round a decimal to the nearest fraction?

Question

Not sure if that is the right way to ask this or not but here is the problem.

Given a latitude of 26.746346081599476, how do I find the number 26.75 as the 16th greater than the number and 26.6875 as the 16th lower than the number?

26.0
26.0625
26.125
26.1875
26.25
26.3125
26.375
26.4375
26.5
26.5625
26.625
26.6875
My Number: 26.746346081599476
26.75
26.8125
26.875
26.9375
27.0

I'm using JavaScript so an answer in that would be helpful but not necessary. I could brute force it but I'm looking for the elegant way to do it.

The bigger picture is that I want to create standard tiles for a mapping application I'm working on. We are using Bing maps and I am loading data on-demand, every time the user pans or zooms in. It would be nice to take advantage of server side caching for these requests so if I standardize the queries sent to the server I would get some cache hits. If I don't standardize the requests to the server it is highly unlikely that the same user would be viewing the exact some location at the same time.

So there is a higher chance of getting cache hits with: /path/data.json?tl=26.6875,-80.6875&br=26.75,-80.75 than with: /path/data.json?tl=26.74946187679896,-80.10930061340332&br=26.743234270702878,-80.09607195854187

Any outside the box answers are welcome as well.

Answer 1

To find the nearest multiples of 1/n:

lower_bound = 1.0 / n * Math.floor(n * your_number);
upper_bound = 1.0 / n * Math.ceil(n * your_number);

You may want to use some special handling if your number is already a multiple of 1/16.

// alternate solution so that lower_bound <= your_number < upper_bound
lower_bound = 1.0 / n * Math.floor(n * your_number);
upper_bound = 1.0 / n * Math.floor(n * your_number + 1.0);